BFS iff vertex iff extreme point
Dependencies:
- Extreme point of a convex set
- Vertex of a set
- Vertex implies extreme point
- Basic feasible solutions
- Extreme point iff BFS
- BFS is vertex
Let $P$ be a polyhedron and $x \in P$. Then $x$ is a BFS of $P$ iff $x$ is an extreme point of $P$ iff $x$ is a vertex of $P$.
Proof
Follows directly from the dependencies.
Dependency for: None
Info:
- Depth: 10
- Number of transitive dependencies: 48
Transitive dependencies:
- /linear-algebra/vector-spaces/condition-for-subspace
- /linear-algebra/matrices/gauss-jordan-algo
- /sets-and-relations/equivalence-relation
- Group
- Ring
- Polynomial
- Integral Domain
- Comparing coefficients of a polynomial with disjoint variables
- Field
- Vector Space
- Linear independence
- Span
- Inner product space
- Semiring
- Matrix
- Stacking
- System of linear equations
- Product of stacked matrices
- Matrix multiplication is associative
- Reduced Row Echelon Form (RREF)
- Matrices over a field form a vector space
- Row space
- Elementary row operation
- Every elementary row operation has a unique inverse
- Row equivalence of matrices
- Row equivalent matrices have the same row space
- RREF is unique
- Identity matrix
- Inverse of a matrix
- Inverse of product
- Elementary row operation is matrix pre-multiplication
- Row equivalence matrix
- Equations with row equivalent matrices have the same solution set
- Rank of a matrix
- Basis of a vector space
- Linearly independent set is not bigger than a span
- Homogeneous linear equations with more variables than equations
- Rank of a homogenous system of linear equations
- Cone
- Convex combination and convex hull
- Vertex of a set
- Convex set
- Polyhedral set and polyhedral cone
- Basic feasible solutions
- BFS is vertex
- Extreme point of a convex set
- Extreme point iff BFS
- Vertex implies extreme point