Row equivalent matrices have the same row space
Dependencies:
Let $A$ and $B$ be 2 matrices over a field. Then $A$ and $B$ are row-equivalent implies that $A$ and $B$ have the same row space.
Proof
Suppose $B$ is obtained from $A$ via an elementary row operation $R$. Then each row of $B$ is a linear combination of the rows of $A$.
Let $x$ be an element in the row space of $B$. $x$ is a linear combination of the rows of $B$, which are linear combinations of the rows of $A$. Therefore, $x$ is a linear combination of the rows of $A$. Therefore, $x$ is in the row space of $A$. Therefore, row space of $B$ is a subset of the row space of $A$.
Since, every elementary row operation in a field has an inverse, $A$ can be obtained from $B$ via the elementary row operation $R^{-1}$. Therefore, row space of $A$ is a subset of the row space of $B$.
This means that if one matrix can be obtained by an elementary row operation on the other matrix, then those matrices have the same row space. Therefore, any 2 matrices which are row equivalent have the same row space.
Dependency for:
Info:
- Depth: 6
- Number of transitive dependencies: 13
Transitive dependencies:
- /linear-algebra/vector-spaces/condition-for-subspace
- /sets-and-relations/equivalence-relation
- Group
- Ring
- Field
- Vector Space
- Semiring
- Matrix
- Matrices over a field form a vector space
- Row space
- Elementary row operation
- Every elementary row operation has a unique inverse
- Row equivalence of matrices