Linear independence

Dependencies:

  1. Vector Space

Let S={v1,v2,,vn} be a subset of vector space V over field F. Then S is linearly independent iff

(a1,a2,,an)Fn,(i=1naivi=0(i,ai=0))

This can also be stated as

(a1,a2,,an)0Fn,i=1naivi0

This is equivalent to saying that "no vector in S is a linear combination of the rest of the elements of S". When a vector v in S is a linear combination of the other elements of S, v is said to be linearly dependent in S.

An empty set is defined to be linearly independent.

When S is of infinite size, then it is linearly dependent iff it has a subset of finite size which is linearly dependent.

Proof

Let S be linearly dependent. (a1,a2,,an)0Fn,i=1naivi=0.

(a1,a2,,an)0k,ak0.

i=1naivi=0i=1k1aivi+akvk+i=k+1naivi=0akvk=i=1k1(ai)vi+i=k+1n(ai)vivk=i=1k1(ak1ai)vi+i=k+1n(ak1ai)vi

Therefore, vk is a linear combination of the rest of the vectors in S.

Conversely, assume vk is a linear combination of the rest of the vectors in S.

vk=i=1k1aivi+i=k+1naivii=1k1aivi+(1)vk+i=k+1naivi=0

Therefore, a linear combination of S is 0 where all coefficients are not 0. Therefore, S is linearly dependent.

Dependency for:

  1. Extreme point iff BFS
  2. Pointing a polyhedron
  3. Basic feasible solutions
  4. Eigenvectors of distinct eigenvalues are linearly independent
  5. A is diagonalizable iff there are n linearly independent eigenvectors
  6. A set of mutually orthogonal vectors is linearly independent
  7. Gram-Schmidt Process
  8. Joining orthogonal linindep sets
  9. Incrementing a linearly independent set
  10. Linearly independent set is not bigger than a span
  11. span(A)=span(B) & |A|=|B| & A is linindep ⟹ B is linindep
  12. Affine independence (incomplete)
  13. Decrementing a span
  14. Basis of a vector space
  15. Vector matroid

Info:

Transitive dependencies:

  1. Group
  2. Ring
  3. Field
  4. Vector Space