Linear independence
Dependencies:
Let $S = \{v_1, v_2, \ldots, v_n\}$ be a subset of vector space $V$ over field $F$. Then $S$ is linearly independent iff
\[ \forall (a_1, a_2, \ldots, a_n) \in F^n, \left (\sum_{i=1}^n a_iv_i = 0 \Rightarrow (\forall i, a_i = 0 )\right) \]
This can also be stated as
\[ \forall (a_1, a_2, \ldots, a_n) \neq 0 \in F^n, \sum_{i=1}^n a_iv_i \neq 0 \]
This is equivalent to saying that "no vector in $S$ is a linear combination of the rest of the elements of $S$". When a vector $v$ in $S$ is a linear combination of the other elements of $S$, $v$ is said to be linearly dependent in $S$.
An empty set is defined to be linearly independent.
When $S$ is of infinite size, then it is linearly dependent iff it has a subset of finite size which is linearly dependent.
Proof
Let $S$ be linearly dependent. $\Rightarrow \exists (a_1, a_2, \ldots, a_n) \neq 0 \in F^n, \sum_{i=1}^n a_iv_i = 0$.
$(a_1, a_2, \ldots, a_n) \neq 0 \iff \exists k, a_k \neq 0$.
\begin{align} & \sum_{i=1}^n a_iv_i = 0 \\ &\Rightarrow \sum_{i=1}^{k-1} a_iv_i + a_kv_k + \sum_{i=k+1}^n a_iv_i = 0 \\ &\Rightarrow a_kv_k = \sum_{i=1}^{k-1} (-a_i)v_i + \sum_{i=k+1}^n (-a_i)v_i \\ &\Rightarrow v_k = \sum_{i=1}^{k-1} (-a_k^{-1}a_i)v_i + \sum_{i=k+1}^n (-a_k^{-1}a_i)v_i \end{align}
Therefore, $v_k$ is a linear combination of the rest of the vectors in $S$.
Conversely, assume $v_k$ is a linear combination of the rest of the vectors in $S$.
\[ v_k = \sum_{i=1}^{k-1} a_iv_i + \sum_{i=k+1}^n a_iv_i \implies \sum_{i=1}^{k-1} a_iv_i + (-1)v_k + \sum_{i=k+1}^n a_iv_i = 0 \]
Therefore, a linear combination of $S$ is 0 where all coefficients are not 0. Therefore, $S$ is linearly dependent.
Dependency for:
- Extreme point iff BFS
- Pointing a polyhedron
- Basic feasible solutions
- Eigenvectors of distinct eigenvalues are linearly independent
- A is diagonalizable iff there are n linearly independent eigenvectors
- A set of mutually orthogonal vectors is linearly independent
- Gram-Schmidt Process
- Joining orthogonal linindep sets
- Incrementing a linearly independent set
- Linearly independent set is not bigger than a span
- span(A)=span(B) & |A|=|B| & A is linindep ⟹ B is linindep
- Affine independence (incomplete)
- Decrementing a span
- Basis of a vector space
- Vector matroid
Info:
- Depth: 4
- Number of transitive dependencies: 4