span(A)=span(B) & |A|=|B| & A is linindep ⟹ B is linindep
Dependencies:
- Vector Space
- Linear independence
- Span
- Decrementing a span
- Linearly independent set is not bigger than a span
$\newcommand{Span}{\operatorname{span}}$ Let $A$ and $B$ be sets of vectors such that $\Span(A) = \Span(B)$ and $|A| = |B|$ and $A$ is linearly independent. Then $B$ is also linearly independent.
Proof
Let $V = \Span(A) = \Span(B)$. Suppose $B$ is linearly dependent. Then $\exists v \in B$ such that $\Span(B) = \Span(B - \{v\})$. Since $A$ is linearly independent, $A \subseteq V$, and $B - \{v\}$ spans $V$, we get $|A| \le |B - \{v\}| = |B|-1$, which is a contradiction. Hence, $B$ is linearly independent.
Dependency for: None
Info:
- Depth: 6
- Number of transitive dependencies: 38
Transitive dependencies:
- /linear-algebra/vector-spaces/condition-for-subspace
- /linear-algebra/matrices/gauss-jordan-algo
- /sets-and-relations/equivalence-relation
- Group
- Ring
- Polynomial
- Integral Domain
- Comparing coefficients of a polynomial with disjoint variables
- Field
- Vector Space
- Linear independence
- Span
- Decrementing a span
- Semiring
- Matrix
- Stacking
- System of linear equations
- Product of stacked matrices
- Matrix multiplication is associative
- Reduced Row Echelon Form (RREF)
- Matrices over a field form a vector space
- Row space
- Elementary row operation
- Every elementary row operation has a unique inverse
- Row equivalence of matrices
- Row equivalent matrices have the same row space
- RREF is unique
- Identity matrix
- Inverse of a matrix
- Inverse of product
- Elementary row operation is matrix pre-multiplication
- Row equivalence matrix
- Equations with row equivalent matrices have the same solution set
- Linearly independent set is not bigger than a span
- Homogeneous linear equations with more variables than equations
- Rank of a homogenous system of linear equations
- Rank of a matrix
- Basis of a vector space