Preserving a basis by replacing a vector
Dependencies:
Let $B = [u_1, u_2, \ldots, u_n]$ be a basis of a vector space $V$. Let $w = \sum_{i=1}^n \alpha_i u_i$. Then $B' = [u_1, u_2, \ldots, u_{k-1}, w, u_{k+1}, \ldots, u_n]$ is a basis of $V$ iff $\alpha_k \neq 0$.
Proof
Without loss of generality, assume $k = n$. Since $B'$ contains $n = \dim(V)$ vectors, $B'$ is a basis of $V$ iff $B'$ is linearly independent. We will now try to prove that $\alpha_n = 0$ iff $B'$ is linearly dependent.
Assume $\alpha_n = 0$. Then $b = \sum_{i=1}^{n-1} \alpha_i u_i$, so $B'$ is linearly dependent.
Let $B'$ be linearly dependent. Then for some non-zero vector $[\mu_1, \mu_2, \ldots, \mu_n]$, we have \begin{align} & \sum_{i=1}^{n-1} \mu_iu_i + \mu_nb_n = 0 \\ &\iff \sum_{i=1}^{n-1} \mu_iu_i + \mu_n\left(\sum_{i=1}^n \alpha_iu_i\right) = 0 \\ &\iff \sum_{i=1}^{n-1} (\mu_i + \mu_n\alpha_i)u_i + \mu_n\alpha_nu_n = 0 \end{align}
Since $B$ is a linearly independent, we get $\mu_n\alpha_n = 0$ and $\mu_i + \mu_n\alpha_i = 0$ for all $1 \le i < n$. If $\mu_n = 0$, then $\mu_i = -\mu_n\alpha_i = 0$, which is a contradiction since $[\mu_1, \mu_2, \ldots, \mu_n]$ is a non-zero vector. Hence, $\mu_n \neq 0$, and so $\alpha_n = 0$.
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- Depth: 7
- Number of transitive dependencies: 39
Transitive dependencies:
- /linear-algebra/vector-spaces/condition-for-subspace
- /linear-algebra/matrices/gauss-jordan-algo
- /sets-and-relations/equivalence-relation
- Group
- Ring
- Polynomial
- Integral Domain
- Comparing coefficients of a polynomial with disjoint variables
- Field
- Vector Space
- Linear independence
- Span
- Incrementing a linearly independent set
- Semiring
- Matrix
- Stacking
- System of linear equations
- Product of stacked matrices
- Matrix multiplication is associative
- Reduced Row Echelon Form (RREF)
- Matrices over a field form a vector space
- Row space
- Elementary row operation
- Every elementary row operation has a unique inverse
- Row equivalence of matrices
- Row equivalent matrices have the same row space
- RREF is unique
- Identity matrix
- Inverse of a matrix
- Inverse of product
- Elementary row operation is matrix pre-multiplication
- Row equivalence matrix
- Equations with row equivalent matrices have the same solution set
- Basis of a vector space
- Linearly independent set is not bigger than a span
- Homogeneous linear equations with more variables than equations
- Rank of a homogenous system of linear equations
- Rank of a matrix
- A set of dim(V) linearly independent vectors is a basis