Basis changer
Dependencies:
Let $U$ and $V$ be vector spaces with bases $P$ and $Q$ respectively. Let $\phi$ be a bijection from $P$ to $Q$. If $P$ and $Q$ are finite, a bijection exists between them iff $|P| = |Q|$; the bijection maps the $i^{\textrm{th}}$ element of $P$ to the $i^{\textrm{th}}$ element of $Q$.
A basis changer $T: U \mapsto V$ is a bijection of the form:
\[ T\left(\sum_{p \in P} a_p p \right) = \sum_{p \in P} a_p \phi(p) \]
Proof
Since every vector in $U$ can be expressed as a unique linear combination of vectors in $P$, $T$ is well-defined.
Since every vector in $Q$ can be expressed as a unique linear combination of vectors in $Q$, $T$ is onto.
\begin{align} & T\left(\sum_{p \in P} a_p p\right) = T\left(\sum_{p \in P} b_p p\right) \\ &\Rightarrow \sum_{p \in P} a_p \phi(p) = \sum_{p \in P} b_p \phi(p) \\ &\Rightarrow \forall p \in P, a_p = b_p \tag{$\because$ of unique representation in $V$} \\ &\Rightarrow \sum_{p \in P} a_p p = \sum_{p \in P} b_p p \end{align}
Therefore, $T$ is one-to-one. Therefore, $T$ is a bijection.
Dependency for:
Info:
- Depth: 7
- Number of transitive dependencies: 38
Transitive dependencies:
- /linear-algebra/vector-spaces/condition-for-subspace
- /linear-algebra/matrices/gauss-jordan-algo
- /sets-and-relations/equivalence-relation
- Group
- Ring
- Polynomial
- Integral Domain
- Comparing coefficients of a polynomial with disjoint variables
- Field
- Vector Space
- Linear independence
- Span
- Semiring
- Matrix
- Stacking
- System of linear equations
- Product of stacked matrices
- Matrix multiplication is associative
- Reduced Row Echelon Form (RREF)
- Matrices over a field form a vector space
- Row space
- Elementary row operation
- Every elementary row operation has a unique inverse
- Row equivalence of matrices
- Row equivalent matrices have the same row space
- RREF is unique
- Identity matrix
- Inverse of a matrix
- Inverse of product
- Elementary row operation is matrix pre-multiplication
- Row equivalence matrix
- Equations with row equivalent matrices have the same solution set
- Basis of a vector space
- Linearly independent set is not bigger than a span
- Homogeneous linear equations with more variables than equations
- Rank of a homogenous system of linear equations
- Rank of a matrix
- Coordinatization over a basis