Additive chores and binary marginals
Dependencies:
- Fair division
- PROP1
- Minimum fair share
- EF1
- PROPx
- Maximin share allocations
- EFX
- Epistemic fairness
- AnyPrice share
- Additive set function
- Bound on k extreme values
- PROP-unsat implies someone is superPROP
- Restricted agents, pairwise fairness, and groupwise fairness
- EF1 implies PROP1
$\newcommand{\defeq}{:=}$ $\newcommand{\ceil}[1]{\lceil #1 \rceil}$ $\newcommand{\MMS}{\mathrm{MMS}}$ $\newcommand{\APS}{\mathrm{APS}}$ Let $([n], M, V, w)$ be a fair division instance of indivisible chores, where each agent $i$ has entitlement $w_i$. For some agent $i$, let $v_i$ be additive and $v_i(c) \in \{0, 1\}$ for all $c \in M$. Let $M_- \defeq \{c \in M: v_i(c) = 1\}$ and $m \defeq |M_-|$. Then for any allocation $A$,
- $i$ is PROP1-satisfied by $A$ iff $d_i(A_i) ≤ \ceil{w_im}$.
- $i$ is PROPx-satisfied by $A$ iff $d_i(A_i) ≤ \ceil{w_im}$.
- $\APS_i = -\ceil{w_im}$.
- If $i$ is EF1-satisfied by $A$, then $i$ is also groupwise-APS-satisfied by $A$.
Furthermore, when entitlements are equal, we have
- If $i$ is M1S-satisfied by $A$, then $d_i(A_i) ≤ \ceil{m/n}$.
- $\MMS_i = -\ceil{m/n}$.
- If $d_i(A_i) ≤ \ceil{m/n}$, then $i$ is EEFX-satisfied by $A$.
Proof
The statements about PROP1, PROPx, and MMS are trivial.
Set the price of each chore to its value. Then $i$'s budget is $-w_im$, so the maximum value $i$ can buy is $-\ceil{w_im}$. Hence, $\APS_i ≤ -\ceil{w_im}$.
For any non-positive price vector $p$, let $S$ be the cheapest $\ceil{w_im}$ chores. Then $p(S) ≤ \frac{\ceil{w_im}}{m}p(M) ≤ w_ip(M)$. Hence, $S$ is affordable, and has disutility at most $\ceil{w_im}$. Hence, $\APS_i ≥ -\ceil{w_im}$. Therefore, $\APS_i = \ceil{w_im}$.
Points 1 and 3 show that if an allocation is PROP1-satisfied, then it is also APS-satisfied. Suppose $i$ is EF1-satisfied by $A$. Pick a subset $S$ of agents containing $i$. Let $B$ be the allocation restricted to $S$. Then $i$ is also EF1-satisfied by $B$, and so, $i$ is PROP1-satisfied by $B$, and hence, $i$ is APS-satisfied by $B$. Since this holds for every subset $S$, we get that $i$ is groupwise-APS-satisfied by $A$.
Suppose $i$ is M1S-satisfied by $A$. Let $Y$ be $i$'s M1S-certificate for $A$. Suppose $d_i(Y_i) ≥ \ceil{m/n}+1$. Then $d_i(Y_i) > m/n = d_i(M)/n$, so there exists another agent $j$ such that $d_i(Y_j) < v_i(M)/n = m/n$. Hence, $d_i(Y_j) ≤ \ceil{m/n}-1$. Then $i$ EF1-envies $j$, which contradicts the fact that $Y$ is $i$'s M1S-certificate for $A$. Hence, $d_i(A_i) ≤ d_i(Y_i) ≤ \ceil{m/n}$.
Suppose $d_i(A_i) ≤ \ceil{m/n}$. Create another allocation $B$ where $B_i = A_i$ and give at least $\ceil{m/n}-1$ chores of disutility 1 to the other agents. This is possible because $\ceil{m/n} + (n-1)(\ceil{m/n}-1) = n(\ceil{m/n}-1) + 1 < m + 1$. Then $i$ is EFX-satisfied by $B$, so $i$ is EEFX-satisfied by $A$.
Dependency for: None
Info:
- Depth: 7
- Number of transitive dependencies: 26
Transitive dependencies:
- /sets-and-relations/countable-set
- /analysis/sup-inf
- σ-algebra
- Set function
- Fair division
- Proportional allocation
- Restricted agents, pairwise fairness, and groupwise fairness
- Envy-freeness
- PROP1
- Epistemic fairness
- Minimum fair share
- EF1
- Maximin share of a set function
- Maximin share allocations
- Additive set function
- Subadditive and superadditive set functions
- PROP-unsat implies someone is superPROP
- EF1 implies PROP1
- Submodular function
- PROPx
- EFX
- Optimization: Dual and Lagrangian
- Dual of a linear program
- Linear programming: strong duality (incomplete)
- AnyPrice share
- Bound on k extreme values