Expectation of product of independent random variables (incomplete)
Dependencies: (incomplete)
Let $X_1, X_2, \ldots, X_n$ be independent real-valued random variables. Then $\newcommand{\E}{\operatorname{E}}$ \[ \E\left( \prod_{i=1}^n X_i \right) = \prod_{i=1}^n \E(X_i) \]
Proof
For $n=0$ and $n=1$, this is trivially true.
The theorem can also be proven for $n=2$ (proof pending). We can maybe prove this using Fubini's theorem in the general case. For discrete random variables, the proof isn't hard.
For $n \ge 3$, we can prove the theorem by induction. Suppose the theorem is true for up to $n-1$ random variables. If all $X_i$ are independent, then $X_n$ and $X_1X_2\ldots X_{n-1}$ are independent. \begin{align} & \E\left(\prod_{i=1}^n X_i\right) \\ &= \E\left(\prod_{i=1}^{n-1} X_i\right)\E(X_n) \tag{induction hypothesis for 2 variables} \\ &= \left(\prod_{i=1}^{n-1} \E(X_i)\right) \E(X_n) \tag{induction hypothesis for $n-1$ variables} \\ &= \prod_{i=1}^n \E(X_i) \end{align}
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- /analysis/topological-space
- /sets-and-relations/countable-set
- /sets-and-relations/de-morgan-laws
- /measure-theory/lebesgue-integral
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- Generators of the real Borel algebra (incomplete)
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- Independence of random variables (incomplete)