Interior point of polyhedron
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$\newcommand{\xhat}{\widehat{x}}$ Let $P = \{x \in \mathbb{R}^n: (a_i^Tx \ge b_i, \forall i \in I) \wedge (a_i^Tx = b_i, \forall i \in E)\}$ be a non-empty polyhedron. Suppose $P$ doesn't have any implicit equalities. Then $\exists \xhat \in P$ such that $a_i^T\xhat > b_i$ for all $i \in I$. Such an $\xhat$ is called an interior point.
Proof
Let $i \in I$. Since $a_i^Tx \ge b_i$ is not an implicit equality, $\exists x^{(i)} \in P$ such that $a_i^Tx^{(i)} > b_i$. Pick $\xhat = (1/|I|)\sum_{i \in I}x^{(i)}$.
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