Order of element divides order of group
Dependencies:
Let $G$ be a finite group and $g \in G$. Then $\operatorname{order}(g) \mid |G|$.
Proof
$$ g \in G \Rightarrow \langle g \rangle \subseteq G \Rightarrow |\langle g \rangle| \mid |G| \Rightarrow \operatorname{order}(g) \mid |G| $$
Dependency for:
Info:
- Depth: 5
- Number of transitive dependencies: 14
Transitive dependencies:
- Group
- Coset
- Size of coset equals size of subset
- Identity of a group is unique
- Order of element in finite group is finite
- Subgroup
- Inverse of a group element is unique
- gH = H iff g in H
- Two cosets are either identical or disjoint
- Lagrange's Theorem
- Conditions for a subset to be a subgroup
- Cyclic Group
- Integer Division Theorem
- Order of cyclic subgroup is order of generator