Lagrange's Theorem
Dependencies:
Let $H$ be a subgroup of $G$. Then $|H| \mid |G|$ and number of left cosets of $H$ is $\frac{|G|}{|H|}$.
Proof
$\operatorname{id}(G) \in H \implies \forall g \in G, g \in gH \implies \bigcup_{g \in G} gH = G$
Therefore, the cosets of $H$ span $G$.
Since all cosets are disjoint, size of each coset is $|H|$ and cosets span $G$, there are $\frac{|G|}{|H|}$ cosets, each of size $|H|$.
This also implies $|H| \mid |G|$.
Dependency for:
Info:
- Depth: 4
- Number of transitive dependencies: 6