PROPx implies PROPm
Dependencies:
$\newcommand{\defeq}{:=}$ $\newcommand{\jhat}{\hat{\!\jmath}}$ $\newcommand{\Shat}{\widehat{S}}$ Let $([n], [m], V, w)$ be a fair division instance for indivisible items (where each agent $i$ has entitlement $w_i$). If an agent $i$ is PROPx-satisfied by an allocation $A$, then she is also PROPm-satisfied by $A$.
Proof
Assume (for the sake of contradiction) that there is an allocation $A$ where agent $i$ is PROPx-satisfied but not PROPm-satisfied.
Since $i$ is not PROPm-satisfied, we get $v_i(A_i) ≤ w_iv_i([m])$. Since $i$ is PROPx-satisfied, we get
- $v_i(A_i \setminus S) > w_iv_i([m])$ for all $S \subseteq A_i$ such that $v_i(S \mid A_i \setminus S) < 0$.
- $v_i(A_i \cup S) > w_iv_i([m])$ for all $S \subseteq [m] \setminus A_i$ such that $v_i(S \mid A_i) > 0$.
Since $i$ is not PROPm-satisfied, we get that $T \neq \emptyset$ and $v_i(A_i) + \max(T) ≤ w_iv_i([m])$. Let $\max(T) = \tau_{\jhat} = v_i(\Shat \mid A_i) > 0$. Then $v_i(A_i \cup \Shat) ≤ w_iv_i([m])$, which contradicts the fact that $i$ is PROPx-satisfied by $A$. Hence, if $i$ is PROPx-satisfied by $A$, then she is also PROPm-satisfied by $A$.
Dependency for: None
Info:
- Depth: 7
- Number of transitive dependencies: 8
Transitive dependencies:
- /sets-and-relations/countable-set
- σ-algebra
- Set function
- Fair division
- Proportional allocation
- Submodular function
- PROPx
- PROPm