Extreme direction of convex cone as extreme point of intersection with hyperplane
Dependencies:
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Inner product space
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Convex set
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Cone
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Extreme directions of a convex set
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Extreme point of a convex set
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Convex combination and convex hull
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Inner product is anti-linear in second argument
Let be a convex cone (in an inner product space over ).
Let be a vector such that for all .
Let and .
If is an extreme direction of , then is an extreme point of .
If is an extreme point of , then is an extreme direction of .
Proof
We can assume without loss of generality that is 1, since we can scale .
Two vectors and are called collinear iff .
Let . Let . Then , so .
Suppose is a non-extreme point of .
Then for some
where and .
Note that and are not collinear.
Then ,
so is not an extreme direction of .
Hence, if is an extreme direction of , then is an extreme point of .
Let be an extreme point of . Then .
Suppose is not an extreme direction of .
Then , such that , ,
and such that .
Let and .
Then and .
Hence, we get .
Since, ,
we get that is a strict convex combination of and .
Hence, is not an extreme point of , which is a contradiction.
Hence, is an extreme direction of .
Dependency for:
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Representing point in pointed polyhedral cone
Info:
- Depth: 8
- Number of transitive dependencies: 13
Transitive dependencies:
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/complex-numbers/conjugation-is-homomorphic
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Group
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Ring
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Field
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Vector Space
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Inner product space
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Inner product is anti-linear in second argument
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Cone
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Convex combination and convex hull
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Convex set
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Extreme point of a convex set
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Direction of a convex set and Recession cone
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Extreme directions of a convex set