A cyclic group of order n has ϕ(n) generators
Dependencies:
A cyclic group $\langle a \rangle$ of order $n$ has $\phi(n)$ generators.
Proof
$\operatorname{order}(a^k) = \frac{n}{\gcd(k, n)}$.
For $a^k$ to be a generator, it should have order $n$. So $\gcd(k, n) = 1$. That means $k$ can take $\phi(n)$ values. Therefore, $\langle a \rangle$ has $\phi(n)$ generators.
Dependency for: None
Info:
- Depth: 5
- Number of transitive dependencies: 14
Transitive dependencies:
- Group
- Identity of a group is unique
- Subgroup
- Inverse of a group element is unique
- Conditions for a subset to be a subgroup
- Cyclic Group
- Coprime
- Euler's Totient Function
- Integer Division Theorem
- GCD is the smallest Linear Combination
- Common divisor divides GCD
- gcd(a1/d, a2/d, ..., an/d) = gcd(a1, a_2, ..., an)/d
- If x divides ab and x is coprime to a, then x divides b
- Order of elements in cyclic group