Elementary row operation on stacked matrix
Dependencies:
Let $f$ be an elementary row operation. Then $f([A|B]) = [f(A)|f(B)]$.
Since $[A_1|A_2|\ldots|A_n] = [A_1|[A_2|[\ldots|A_n]\ldots]]$, this result can be generalized to $f([A_1|A_2|\ldots|A_n]) = [f(A_1)|f(A_2)|\ldots|f(A_n)]$.
Proof
A row operation on $[A|B]$ is equivalent to applying that row operation on $A$ and $B$ in parallel.
(Full proof yet to be written)
Dependency for: None
Info:
- Depth: 4
- Number of transitive dependencies: 6