PROP doesn't imply M1S for unit-demand valuations

Dependencies:

  1. Fair division
  2. Proportional allocation
  3. Minimum fair share
  4. EF1
  5. Submodular function

Consider a fair division instance with 2 agents, 3 goods, equal entitlements, and identical valuations. Let $\eps \ge 0$. Let the common valuation function be $v$, where \[ v(S) := \begin{cases} 4 + 2\eps|S| & \textrm{ if } 1 \in S \textrm{ or } 2 \in S \\ 3 + 2\eps|S| & \textrm{ if } S = \{3\} \\ 0 & \textrm{ otherwise} \end{cases}. \] Then $v$ is submodular, and the allocation $A = (\{1, 2\}, \{3\})$ is PROP but not M1S.

Proof that $v$ is submodular

\[ v(g \mid S) = 2\eps + \begin{cases} 0 & \textrm{ if } 1 \in S \textrm{ or } 2 \in S \\ 1 & \textrm{ if } S = \{3\} \\ v(\{g\}) & \textrm{ if } S = \emptyset \end{cases}. \]

We can see that adding elements to $S$ never increases $v(g \mid S)$. Hence, $v$ is submodular.

Proof that $A$ is PROP but not M1S

$A$ is PROP since $v(A_1) = 4+6\eps$, $v(A_2) = 3+2\eps$, and the PROP share is $2+3\eps$.

Suppose $A$ is M1S and agent 2's M1S certificate for $A$ is $B$. Then $v(B_2) ≤ v(A_2) = 3 + 2\eps$, so $B_2 = \{3\}$. Hence, $B_1 = \{1, 2\}$. However, $\min_{g \in B_1} v(B_1 \setminus \{g\}) = 4 + 6\eps > 3 + 2\eps = v(B_2)$. Hence, agent 2 is not EF1-satisfied by $B$, which contradicts the fact that $B$ is agent 2's M1S certificate for $A$. Hence, $A$ is not M1S.

Dependency for: None

Info:

Transitive dependencies:

  1. /sets-and-relations/countable-set
  2. σ-algebra
  3. Set function
  4. Fair division
  5. Proportional allocation
  6. Envy-freeness
  7. Minimum fair share
  8. EF1
  9. Submodular function