Stirling's approximation (incomplete)
Dependencies: Unspecified
For $n \ge 1$, \[ \sqrt{2\pi}n^{n+\frac{1}{2}}e^{-n} \le n! \le en^{n+\frac{1}{2}}e^{-n} \]
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For $n \ge 1$, \[ \sqrt{2\pi}n^{n+\frac{1}{2}}e^{-n} \le n! \le en^{n+\frac{1}{2}}e^{-n} \]