Transposition bijects even and odd permutations
Dependencies:
Let $\lambda_\tau(\sigma) = \tau\sigma$, where $\tau$ is a transposition.
$\lambda_\tau$ is a bijection from the set of even permutations to the set of odd permutations.
Proof
$ \textrm{Let } \lambda_\tau(\sigma_1) = \lambda_\tau(\sigma_2) \implies \tau\sigma_1 = \tau\sigma_2 \implies \sigma_1 = \tau^{-1}\tau\sigma_2 = \sigma_2 $
Therefore, $\lambda_\tau$ is one-to-one.
Let $\mu$ be an odd permutation. Then $\lambda_\tau(\mu) = \tau\mu$ is an even permutation.
$\lambda_\tau(\lambda_\tau(\mu)) = \tau\tau\mu = \mu$. So $\mu$ has an even permutation as a pre-image in $\lambda_\tau$. Therefore, $\lambda_\tau$ is onto.
Therefore, $\lambda_\tau$ is a bijection from even permutations to odd permutations.
Dependency for: None
Info:
- Depth: 6
- Number of transitive dependencies: 10
Transitive dependencies:
- /sets-and-relations/relation-composition-is-associative
- /sets-and-relations/composition-of-bijections-is-a-bijection
- Group
- Subgroup
- Permutation group
- Product of cycles and a transposition
- Permutation is disjoint cycle product
- Product of disjoint cycles is commutative
- Canonical cycle notation of a permutation
- Parity of a permutation